+ 4) ⋅ 3 = 5 ⋅ 3 +
4 ⋅ 3(5 + 4) ⋅ 3 = 9 ⋅ 3 = 27 5 ⋅ 3 + 4 ⋅ 3 = 15 + 12 = 27
(а + b) ⋅ c = a ⋅ c + b ⋅ c
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(5 + 4) ⋅ 3 = 9 ⋅ 3 = 27 5 ⋅ 3 + 4 ⋅ 3 = 15 + 12 = 27
(а + b) ⋅ c = a ⋅ c + b ⋅ c
(а – b) ⋅ c = a ⋅ c – b ⋅ c
Запомни!!!
6 ⋅ х - 6 ⋅ 9 = 6х - 54
Из учебника № 548,
№ 546(г,д,е)
199⋅6=
Раскрытие скобок
(а + b) ⋅ c = a ⋅ c + b ⋅ c
(200-1)⋅6=200⋅6–1⋅6=1200–6=1194
35а + а =
59⋅36+41⋅36=
Вынесение за скобки
общего множителя
a ⋅ c + b ⋅ c = (а + b) ⋅ c
35а + 1а = (35+1)а = 36а
(59+41)⋅36=100⋅36=3600
a ⋅ c - b ⋅ c = (а - b) ⋅ c